Obsolete, please see the latest version
Version 1
An attempt to define syntactical and semantical compatiblity of versions in a formal way. Much derives from the writings of David Orchard, especially the parts on syntactical forward and backward compatibility (though my terminology differs).
- Let U be a set of (specifications of) software processable languages {L1, L2, … Ln}
- This axiomatization does not concern itself with natural language
- The extension of a language Lx is a set of conforming document instances ELx = {Dx1, Dx2, … Dxn}
- Iff ELx = ELy then Lx and Ly are extensionally equivalent
- Lx and Ly may still be different: they may define different semantics for the same syntactical construct
- Iff ELx ? ELy then Lx is an extensional sublanguage of Ly
- Iff ELx ? ELy then Lx is an extensional superlanguage of Ly
- D is the set of all possible documents; or the union of all ELx where Lx ? U
- Iff ELx = ELy then Lx and Ly are extensionally equivalent
- For each Lx ? U there is a set of processors Px = {Px1, Px2, … Pxn} which implement Lx
- Each Pxy exhibits behaviour as defined in Lx
- Processors can produce and consume documents
- Each Pxy produces only documents it can consume itself
- At consumption, Pxy may accept or reject documents
- The behaviour of a processor Pxy of language Lx is a function Bxy
- The function Bxy takes as argument a document, and its value is a processor state
- We assume a single processor state before each function execution, alternatively we could assume a <state, document> tuple as function argument
- If for two processors Pxy and Pxz for language Lx for a document d Bxy(d) = Bxz(d) then the two processors behave similar for d
- Two processor states for language Lx are deemed equivalent if a human with thorough knowledge of language specification Lx considers the states equivalent. Details may vary insofar as the language specification allows it.
- Processor equivalence is not intended to be formally or computably decidable; though in some cases it could be.
- If ?d ( d ? ELx ? Bxy(d) = Bxz(d) ) then Pxy and Pxz are behaviourally equivalent for Lx
- If two processors behave the same for every document which belongs to a language Lx, the processors are behaviourally equivalent for Lx.
- The function Bxy takes as argument a document, and its value is a processor state
- An ideal language specifies all aspects of desired processor behaviour completely and unambiguously; assume all languages in U are ideal
- A processor Px is an exemplary processor of a language Lx if it fully implements language specification Lx; assume all processors for all languages in U are exemplary
- Because they are (defined to be) exemplary, every two processors for a language Lx are behaviourally equivalent
- ELx = { d is a document ? Px accepts d }
- The complement of ELx is the set of everything (normally, every document) which is rejected by Px
- The make set MLx = { d is a document ? Px can produce d }
- A language Lx is syntactically compatible with Ly iff MLx ? ELy and MLy ? ELx
- Two languages are syntactically compatible if they accept the documents produced by each other.
- A language Ln+1 is syntactically backward compatible with Ln iff MLn ? ELn+1 and Ln+1 is a successor of Ln
- A language change is syntactically backward compatible if a new receiver accepts all documents produced by an older sender.
- A language Ln is syntactically forward compatible with Ln+1 iff MLn+1 ? ELn and Ln+1 is a successor of Ln
- A language change is syntactically forward compatible if an old receiver accepts all documents produced by a new sender.
- A document d can be a member of the extension of any number of languages
- Px is an (exemplary) processor of Lx, Py is an (exemplary) processor of language Ly
- Two langauges Lx and Ly are semantically equivalent iff ELx = ELy ? ?d ( (d ? ELx ) ? Bx(d) = By(d) )
- If two languages Lx and Ly take the same documents as input, and their exemplary processors behave the same for every document, the languages are semantically equivalent.
- Two languages can only be compared if their exemplary processors are similar enough to be compared.
- Not every two languages can be compared.
- “Semantic” should not be interpreted in the sense of “formal semantics”.
- The semantical equivalence set of a document d for Lx = { y ? ELx | Bx(d) = Bx(y) }
- Or: SLx,d = { y ? ELx | Bx(d) = Bx(y) }
- The semantical equivalence set of a document d is the set of documents which make a processor behave the same as d
- Semantical equivalence occurs for expressions which are semantically equivalent, such as i = i + 1 and i += 1 for C, or different attribute order in XML etc.
- d ? SLx,d
- Any two semantical equivalence sets of Lx are necessarily disjunct
- If z ? SLx,e were also z ? SLx,d then every member of SLx,e would be in SLx,d and vice versa and thus SLx,d = SLx,e
- Or: SLx,d = { y ? ELx | Bx(d) = Bx(y) }
- A language Ly is a semantical superlanguage of Lx iff ?d ( d ? MLx ? By(d) = Bx(d) )
- For all documents produced by Px, Py behaves the same as Px
- Equivalence in this case should be decided based on Lx; if Ly makes behavioural distinctions which are not mentioned in Lx, behaviour is still the same as far as Lx is concerned
- It follows: ?d ( d ? MLx ? ?SLy,d ( SLy,d ? ELy ? ( SLx,d ? MLx ) ? SLy,d ? By(d) = Bx(d) ) )
- For any document produced by Px, the part of its semantical equivalence set which Px can actually produce, is a subset of the semantical equivalence set of Py for this document
- For all d ? ELx ? d ? MLx there may be many equivalence sets in Ly for which By(d) ? Bx(d)
- In other words: for documents accepted but not produced by Px, Ly may define additional behaviours
- Lx is a semantical sublanguage of Ly iff Ly is a semantical superlanguage of Lx
- For all documents produced by Px, Py behaves the same as Px
- A language Ln+1 is semantically backward compatible with Ln iff Ln+1 is a semantical superlanguage of Ln and Ln+1 is a successor of Ln
- An old sender may expect a newer, but semantically backward compatible, receiver to behave as the sender intended
- A language Ln is semantically forward compatible with Ln+1 iff Ln+1 is a semantical sublanguage of Ln and Ln+1 is a successor of Ln
- Semantic forward compatibility is only possible if a language loses semantics; i.e. it’s processors exhibit less functionality, and produce less diverse documents
- A processor cannot understand what it does not know about yet